4x^2+2x(1000/2x^2)+4x(1000/2x^2)=0

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Solution for 4x^2+2x(1000/2x^2)+4x(1000/2x^2)=0 equation: 



4x^2+2x(1000/2x^2)+4x(1000/2x^2)=0



Domain of the equation: 2x^2)!=0

x!=0/1

x!=0

x∈R



We multiply parentheses

4x^2+2000x^2+4000x^2=0

We add all the numbers together, and all the variables

6004x^2=0

a = 6004; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6004·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12008}=0$

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